# Beta version

BETA TEST VERSION OF THIS ITEM

This online calculator is currently under heavy development. It may or it may NOT work correctly.

You CAN try to use it. You CAN even get the proper results.

However, please VERIFY all results on your own, as the level of completion of this item is NOT CONFIRMED.

Feel free to send any ideas and comments !

This online calculator is currently under heavy development. It may or it may NOT work correctly.

You CAN try to use it. You CAN even get the proper results.

However, please VERIFY all results on your own, as the level of completion of this item is NOT CONFIRMED.

Feel free to send any ideas and comments !

# Inputs data - value and unit, which we're going to convert

Value | ||

Unit | ||

Decimals |

# 1 (debye) is equal to:

# SI

Unit | Symbol | Symbol (plain text) | Value | Notes |

coulomb gigameter | Show source$C \times Gm$ | C × Gm | 3.33564095×10^{-39} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit gigameter (1 Gm).$1\ C \times Gm = 10^9\ C \times m$ |

coulomb megameter | Show source$C \times Mm$ | C × Mm | 3.33564095×10^{-36} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit megameter (1 Mm).$1\ C \times Mm = 10^6\ C \times m$ |

coulomb kilometer | Show source$C \times km$ | C × km | 3.33564095×10^{-33} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit kilometer (1 km).$1\ C \times km = 1000\ C \times m$ |

coulomb meter | Show source$C \times m$ | C × m | 3.33564095×10^{-30} | The basic unit of dipole moment in the SI system. One coulomb times a meter corresponds to a dipole moment occurring between two opposing point charges of one coulomb (1 C), located at a distance of one meter (1 m). |

coulomb decimeter | Show source$C \times dm$ | C × dm | 3.33564095×10^{-29} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit decimeter (1 dm).$1\ C \times dm = 0.1\ C \times m$ |

coulomb centimeter | Show source$C \times cm$ | C × cm | 3.33564095×10^{-28} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit centimeter (1 cm).$1\ C \times cm = 0.01\ C \times m$ |

coulomb milimeter | Show source$C \times mm$ | C × mm | 3.33564095×10^{-27} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit milimeter (1 mm).$1\ C \times mm = 0.001\ C \times m$ |

coulomb micrometer | Show source$C \times \mu m$ | C × µm | 3.33564095×10^{-24} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit micrometer (1 μm).$1\ C \times \mu m = 10^{-6}\ C \times m$ |

coulomb nanometer | Show source$C \times nm$ | C × nm | 3.33564095×10^{-21} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit nanometer (1 nm).$1\ C \times nm = 10^{-9}\ C \times m$ |

coulomb angstrom | Show source$C \times \text{Å}$ | C × Å | 3.33564095×10^{-20} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit angstrem (1 Å).$1\ C \times \text{Å} = 10^{-10}\ C \times m$ |

coulomb nanometer | Show source$C \times pm$ | C × pm | 3.33564095×10^{-18} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit picometer (1 pm).$1\ C \times pm = 10^{-12}\ C \times m$ |

coulomb femtometer | Show source$C \times fm$ | C × fm | 3.33564095×10^{-15} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit femtometer (1 fm).$1\ C \times fm = 10^{-15}\ C \times m$ |

coulomb attometer | Show source$C \times am$ | C × am | 3.33564095×10^{-12} | The derived unit of dipole moment created by multiplying electric charge unit coulomb (1 C) and length unit attometer (1 am).$1\ C \times am = 10^{-18}\ C \times m$ |

# Chemistry and atomic physics

Unit | Symbol | Symbol (plain text) | Value | Notes |

debye | Show source$D$ | D | 1 | Unit of dipole moment derived from the centimeter-gram-second system (CGS). One debye corresponds to a dipole moment occurring between two charges of one ten billionth franklin (10^{-10} Fr) separated by distance of one agstrem (1 Å). Although the CGS system has been displaced by SI units, the debye unit is still often used in atomic physics and to determine the dipole moment of chemical molecules. This fact has purely practical reasons, because most chemical molecules have a dipole moment within range 0-11 debyes.$1\ D = 10^{-10}\ Fr \cdot \text{Å} \approx 3.33564 \cdot 10^{−30}\ C\ \cdot m$ |

atomic unit of electric dipole moment | Show source$au$ | au | 0.393430307 | Unit of dipole moment often used in quantum-mechanical calculations. One atomic unit corresponds to a dipole moment between two elementary charges (e) spaced apart by a distance of one Bohr radius (a_{0}).$1 au = e \cdot a_0 \approx 8.478 353 6255 \cdot 10^{-30}\ C \cdot m$ |

# Some facts

- The
**electric dipole moment**for a system consisting of two or more**point charges**is defined as the below sum:

$\overrightarrow{p} = \sum_{i=1...n}{q_i \overrightarrow{r_i}}$where:

**$\overrightarrow{p}$**- electric dipole moment of the whole system,

**$\overrightarrow{r_i}$**- a vector pointing to the i-th electric charge,

**$q_i$**- value of i-th charge,

**$n$**- number of charges in the system.

- Dipole moment is a
**vector**. - The dipole moment makes sense for
**neutral systems**, i.e. where the sum of all charges is zero:

$\sum_{i=1...n}{q_i} = 0$ - The unit of electric dipole moment in SI system is
**coulomb times meter**:

$C \cdot m$ - Another unit, used mainly by chemists and atomic physics, is
**1 debye**:

$1 D = 3,33564 \cdot 10^{-30} C \cdot m$ - If the system with the dipole moment $\overrightarrow{p}$ is introduced into the external electric field $\overrightarrow{E}$, then the moment of force will act on it is:

$\overrightarrow{M} = \overrightarrow{p} \times \overrightarrow{E}$ - Molecules with
**non-zero dipole moment**are called**polar**. An example of such a molecule is water ($H_2O$). - If the electric charges in the system are
**evenly distributed**, then the dipole moment of such a system is zero. Examples of such systems are**chemical molecules with a symmetrical structure**such as carbon tetrachloride ($CCl_4$). Such molecules are called**apolar**or**non-polar**.

# How to convert

**Enter the number to field "value"**- enter the NUMBER only, no other words, symbols or unit names. You can use dot (**.**) or comma (**,**) to enter fractions.

Examples:- 1000000
- 123,23
- 999.99999

**Find and select your starting unit in field "unit"**. Some unit calculators have huge number of different units to select from - it's just how complicated our world is...**And... you got the result**in the table below. You'll find several results for many different units - we show you all results we know at once. Just find the one you're looking for.

# Tags and links to this website

# What tags this calculator has

# Permalink

This is permalink. Permalink is the link containing your input data. Just copy it and share your work with friends: