Converter of specific heat units
Specific heat capacity units converter - converts units based on various energy units (joules, calories, kilocalories), temperature units (Kelvins, Celsius or Fahrenheit degrees) and mass units (grams, kilograms).

# Beta version#

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# Symbolic algebra

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# Inputs data - value and unit, which we're going to convert#

 Value Unit joule / kilogram / Kelvin [J / (kg × K)]joule / gram / Kelvin [J / (g × K)]calorie (thermochemical) / kilogram / Kelvin [calth / (kg × K)]calorie (thermochemical) / gram / Kelvin [calth / (g × K)]calorie (International Table) / kilogram / Kelvin [calIT / (kg × K)]calorie (International Table) / gram / Kelvin [calIT / (g × K)]kilocalorie / kilogram / Kelvin [kcal / (kg × K)]kilocalorie / gram / Kelvin [kcal / (g × K)]joule / kilogram / degree Celsius [J / (kg × °C)]joule / gram / degree Celsius [J / (g × °C)]calorie (thermochemical) / kilogram / degree Celsius [calth / (kg × °C)]calorie (thermochemical) / gram / degree Celsius [calth / (g × °C)]calorie (International Table) / kilogram / degree Celsius [calIT / (kg × °C)]calorie (International Table) / gram / degree Celsius [calIT / (g × °C)]kilocalorie / kilogram / degree Celsius [kcal / (kg × °C)]kilocalorie / gram / degree Celsius [kcal / (g × °C)]joule / kilogram / degree Fahrenheit [J / (kg × °F)]joule / gram / degree Fahrenheit [J / (g × °F)]calorie (thermochemical) / kilogram / degree Fahrenheit [calth / (kg × °F)]calorie (thermochemical) / gram / degree Fahrenheit [calth / (g × °F)]calorie (International Table) / kilogram / degree Fahrenheit [calIT / (kg × °F)]calorie (International Table) / gram / degree Fahrenheit [calIT / (g × °F)]kilocalorie / kilogram / degree Fahrenheit [kcal / (kg × °F)]kilocalorie / gram / degree Fahrenheit [kcal / (g × °F)] Decimals 0123456789

# Popular (temperature in Kelvins)#

 Unit Symbol Symbol(plain text) Value as symbolic Value as numeric Notes Unit conversion formula joule / kilogram / Kelvin Show source$\frac{J}{kg\times K}$ J / (kg × K) Show source$\text{...}$ - The basic specific heat unit in the SI system. The substance has specific heat of one joule per kilograme per kelwin (1 J/kg/K) if heating one kilograme sample (1 kg) by one kelvin (1 K) requires delivery of one joule of energy (1 J). Show source$...$ joule / gram / Kelvin Show source$\frac{J}{g\times K}$ J / (g × K) Show source$\text{...}$ - The basic specific heat unit in the SI system. The substance has specific heat of one joule per grame per kelwin (1 J/g/K) if heating one grame sample (1 g) by one kelvin (1 K) requires delivery of one joule of energy (1 J).$1\ \frac{J}{g \times K} = \frac{1\ J}{0.001\ kg \times K} = \frac{1000\ J}{kg \times K}$ Show source$...$ calorie (thermochemical) / kilogram / Kelvin Show source$\frac{cal_{th}}{kg\times K}$ calth / (kg × K) Show source$\text{...}$ - The basic specific heat unit in the SI system. The substance has specific heat of one joule per kilograme per kelwin (1 calTH/kg/K) if heating one kilograme sample (1 kg) by one kelvin (1 K) requires delivery of one joule of energy (1 calTH).$1\ \frac{cal_{TH}}{kg \times K} = \frac{4.184\ J}{kg \times K}$ Show source$...$ calorie (thermochemical) / gram / Kelvin Show source$\frac{cal_{th}}{g\times K}$ calth / (g × K) Show source$\text{...}$ - The basic specific heat unit in the SI system. The substance has specific heat of one joule per grame per kelwin (1 calTH/g/K) if heating one grame sample (1 g) by one kelvin (1 K) requires delivery of one joule of energy (1 calTH).$1\ \frac{cal_{TH}}{g \times K} = \frac{1\ cal_{TH}}{0.001\ kg \times K} = \frac{1000\ cal_{TH}}{kg \times K}$ Show source$...$ calorie (International Table) / kilogram / Kelvin Show source$\frac{cal_{IT}}{kg\times K}$ calIT / (kg × K) Show source$\text{...}$ - The basic specific heat unit in the SI system. The substance has specific heat of one joule per kilograme per kelwin (1 calIT/kg/K) if heating one kilograme sample (1 kg) by one kelvin (1 K) requires delivery of one joule of energy (1 calIT).$1\ \frac{cal_{IT}}{kg \times K} = \frac{4.1868\ J}{kg \times K}$ Show source$...$ calorie (International Table) / gram / Kelvin Show source$\frac{cal_{IT}}{g\times K}$ calIT / (g × K) Show source$\text{...}$ - The basic specific heat unit in the SI system. The substance has specific heat of one joule per grame per kelwin (1 calIT/g/K) if heating one grame sample (1 g) by one kelvin (1 K) requires delivery of one joule of energy (1 calIT).$1\ \frac{cal_{IT}}{g \times K} = \frac{1\ cal_{IT}}{0.001\ kg \times K} = \frac{1000\ cal_{IT}}{kg \times K}$ Show source$...$ kilocalorie / kilogram / Kelvin Show source$\frac{kcal}{kg\times K}$ kcal / (kg × K) Show source$\text{...}$ - The basic specific heat unit in the SI system. The substance has specific heat of one joule per kilograme per kelwin (1 kcal/kg/K) if heating one kilograme sample (1 kg) by one kelvin (1 K) requires delivery of one joule of energy (1 kcal).$1\ \frac{kcal}{kg \times K} = \frac{1000\ cal_{IT}}{kg \times K}$ Show source$...$ kilocalorie / gram / Kelvin Show source$\frac{kcal}{g\times K}$ kcal / (g × K) Show source$\text{...}$ - The basic specific heat unit in the SI system. The substance has specific heat of one joule per grame per kelwin (1 kcal/g/K) if heating one grame sample (1 g) by one kelvin (1 K) requires delivery of one joule of energy (1 kcal).$1\ \frac{kcal}{g \times K} = \frac{\cancel{1000}\ cal_{IT}}{\cancel{0.001}\ kg \times K} = 1\ \frac{cal_{IT}}{kg \times K}$ Show source$...$

# Popular (temperature in Celsius degrees)#

 Unit Symbol Symbol(plain text) Value as symbolic Value as numeric Notes Unit conversion formula joule / kilogram / degree Celsius Show source$\frac{J}{kg\times ^\circ C}$ J / (kg × °C) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per celsius degree (1 J/kg/F) if heating one kilograme sample (1 kg) by one Celsius degree (1 K) requires delivery of one joule of energy (1 J).$1\ \frac{J}{kg \times ^{\circ}C} = 1\ \frac{J}{kg \times K}$ Show source$...$ joule / gram / degree Celsius Show source$\frac{J}{g\times ^\circ C}$ J / (g × °C) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per grame per celsius degree (1 J/g/F) if heating one grame sample (1 g) by one Celsius degree (1 K) requires delivery of one joule of energy (1 J).$1\ \frac{J}{g \times ^{\circ}C} = \frac{1\ J}{0.001\ kg \times ^{\circ}C} = \frac{1000\ J}{kg \times ^{\circ}C}$ Show source$...$ calorie (thermochemical) / kilogram / degree Celsius Show source$\frac{cal_{th}}{kg\times ^\circ C}$ calth / (kg × °C) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per celsius degree (1 calTH/kg/F) if heating one kilograme sample (1 kg) by one Celsius degree (1 K) requires delivery of one joule of energy (1 calTH).$1\ \frac{cal_{TH}}{kg \times ^{\circ}C} = \frac{4.184\ J}{kg \times ^{\circ}C}$ Show source$...$ calorie (thermochemical) / gram / degree Celsius Show source$\frac{cal_{th}}{g\times ^\circ C}$ calth / (g × °C) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per grame per celsius degree (1 calTH/g/F) if heating one grame sample (1 g) by one Celsius degree (1 K) requires delivery of one joule of energy (1 calTH).$1\ \frac{cal_{TH}}{g \times ^{\circ}C} = \frac{1\ cal_{TH}}{0.001\ kg \times ^{\circ}C} = \frac{1000\ cal_{TH}}{kg \times ^{\circ}C}$ Show source$...$ calorie (International Table) / kilogram / degree Celsius Show source$\frac{cal_{IT}}{kg\times ^\circ C}$ calIT / (kg × °C) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per celsius degree (1 calIT/kg/F) if heating one kilograme sample (1 kg) by one Celsius degree (1 K) requires delivery of one joule of energy (1 calIT).$1\ \frac{cal_{IT}}{kg \times ^{\circ}C} = \frac{4.1868\ J}{kg \times ^{\circ}C}$ Show source$...$ calorie (International Table) / gram / degree Celsius Show source$\frac{cal_{IT}}{g\times ^\circ C}$ calIT / (g × °C) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per grame per celsius degree (1 calIT/g/F) if heating one grame sample (1 g) by one Celsius degree (1 K) requires delivery of one joule of energy (1 calIT).$1\ \frac{cal_{IT}}{g \times ^{\circ}C} = \frac{1\ cal_{IT}}{0.001\ kg \times ^{\circ}C} = \frac{1000\ cal_{IT}}{kg \times ^{\circ}C}$ Show source$...$ kilocalorie / kilogram / degree Celsius Show source$\frac{kcal}{kg\times ^\circ C}$ kcal / (kg × °C) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per celsius degree (1 kcal/kg/F) if heating one kilograme sample (1 kg) by one Celsius degree (1 K) requires delivery of one joule of energy (1 kcal).$1\ \frac{kcal}{kg \times ^{\circ}C} = \frac{1000\ cal_{IT}}{kg \times ^{\circ}C}$ Show source$...$ kilocalorie / gram / degree Celsius Show source$\frac{kcal}{g\times ^\circ C}$ kcal / (g × °C) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per grame per celsius degree (1 kcal/g/F) if heating one grame sample (1 g) by one Celsius degree (1 K) requires delivery of one joule of energy (1 kcal).$1\ \frac{kcal}{g \times ^{\circ}C} = \frac{\cancel{1000}\ cal_{IT}}{\cancel{0.001}\ kg \times ^{\circ}C} = 1\ \frac{cal_{IT}}{kg \times ^{\circ}C}$ Show source$...$

# Popular (temperature in Fahrenheit degrees)#

 Unit Symbol Symbol(plain text) Value as symbolic Value as numeric Notes Unit conversion formula joule / kilogram / degree Fahrenheit Show source$\frac{J}{kg\times ^\circ F}$ J / (kg × °F) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per Fahrenheit degree (1 J/kg/F) if heating one kilograme sample (1 kg) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 J).$1\ \frac{J}{kg \times ^{\circ}F} = 1.8\ \frac{J}{kg \times K}$ Show source$...$ joule / gram / degree Fahrenheit Show source$\frac{J}{g\times ^\circ F}$ J / (g × °F) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per grame per Fahrenheit degree (1 J/g/F) if heating one grame sample (1 g) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 J).$1\ \frac{J}{g \times ^{\circ}F} = \frac{1\ J}{0.001\ kg \times ^{\circ}F} = \frac{1000\ J}{kg \times ^{\circ}F}$ Show source$...$ calorie (thermochemical) / kilogram / degree Fahrenheit Show source$\frac{cal_{th}}{kg\times ^\circ F}$ calth / (kg × °F) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per Fahrenheit degree (1 calTH/kg/F) if heating one kilograme sample (1 kg) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 calTH).$1\ \frac{cal_{TH}}{kg \times ^{\circ}F} = \frac{4.184\ F}{kg \times ^{\circ}F}$ Show source$...$ calorie (thermochemical) / gram / degree Fahrenheit Show source$\frac{cal_{th}}{g\times ^\circ F}$ calth / (g × °F) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per grame per Fahrenheit degree (1 calTH/g/F) if heating one grame sample (1 g) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 calTH).$1\ \frac{cal_{TH}}{g \times ^{\circ}F} = \frac{1\ cal_{TH}}{0.001\ kg \times ^{\circ}F} = \frac{1000\ cal_{TH}}{kg \times ^{\circ}F}$ Show source$...$ calorie (International Table) / kilogram / degree Fahrenheit Show source$\frac{cal_{IT}}{kg\times ^\circ F}$ calIT / (kg × °F) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per Fahrenheit degree (1 calIT/kg/F) if heating one kilograme sample (1 kg) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 calIT).$1\ \frac{cal_{IT}}{kg \times ^{\circ}F} = \frac{4.1868\ J}{kg \times ^{\circ}F}$ Show source$...$ calorie (International Table) / gram / degree Fahrenheit Show source$\frac{cal_{IT}}{g\times ^\circ F}$ calIT / (g × °F) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per grame per Fahrenheit degree (1 calIT/g/F) if heating one grame sample (1 g) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 calIT).$1\ \frac{cal_{IT}}{g \times ^{\circ}F} = \frac{1\ cal_{IT}}{0.001\ kg \times ^{\circ}F} = \frac{1000\ cal_{IT}}{kg \times ^{\circ}F}$ Show source$...$ kilocalorie / kilogram / degree Fahrenheit Show source$\frac{kcal}{kg\times ^\circ F}$ kcal / (kg × °F) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per Fahrenheit degree (1 kcal/kg/F) if heating one kilograme sample (1 kg) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 kcal).$1\ \frac{kcal}{kg \times ^{\circ}F} = \frac{1000\ cal_{IT}}{kg \times ^{\circ}F}$ Show source$...$ kilocalorie / gram / degree Fahrenheit Show source$\frac{kcal}{g\times ^\circ F}$ kcal / (g × °F) Show source$\text{...}$ - The non-SI specific heat unit. The substance has specific heat of one joule per grame per Fahrenheit degree (1 kcal/g/F) if heating one grame sample (1 g) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 kcal).$1\ \frac{kcal}{g \times ^{\circ}F} = \frac{\cancel{1000}\ cal_{IT}}{\cancel{0.001}\ kg \times ^{\circ}F} = 1\ \frac{cal_{IT}}{kg \times ^{\circ}F}$ Show source$...$

# Some facts#

• ⓘ Remember: Specific heat is a physical quantity determining the amount of energy (heat) that should be supplied (transferred) to one unit of substance mass to raise the temperature by one unit.
• The basic specific heat unit in the SI system is joule per kilogram per kelvin:
$\dfrac{J}{kg × K}$
• Specific heat is a property of substance (the so-called material constant). Also, it depends on external conditions: pressure and temperature.
• The specific heat tells us how difficult it is to heat the given body. Substances with low specific heat change their temperature easily, whereas high ones require much more energy delivered to achieve identical effect.
• To calculate the specific heat of the selected substance, we can use the following formula:
$c = \dfrac{\Delta Q}{m \times \Delta T}$
where:
• $c$ - specific heat of the substance,
• $\Delta Q$ - amount of heat delivered,
• $m$ - mass of the heated sample,
• $\Delta T$ - noted temperature change.
• Due to the high compressibility of gases, two values of specific heat are given in their case:
• $C_p$ - specific heat under constant pressure,
• $C_v$ - specific heat under constant volume.
*) Compressibility is the property of a substance meaning that substance changes volume significantly under pressure.

# How to convert#

• Enter the number to field "value" - enter the NUMBER only, no other words, symbols or unit names. You can use dot (.) or comma (,) to enter fractions.
Examples:
• 1000000
• 123,23
• 999.99999
• Find and select your starting unit in field "unit". Some unit calculators have huge number of different units to select from - it's just how complicated our world is...
• And... you got the result in the table below. You'll find several results for many different units - we show you all results we know at once. Just find the one you're looking for.

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