Converter of specific heat units
Specific heat capacity units converter - converts units based on various energy units (joules, calories, kilocalories), temperature units (Kelvins, Celsius or Fahrenheit degrees) and mass units (grams, kilograms).

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Inputs data - value and unit, which we're going to convert#

Value
Unit
Decimals

4189.94189.9 (joule / kilogram / Kelvin) is equal to:#

Popular (temperature in Kelvins)#

UnitSymbolSymbol
(plain text)
Value as symbolicValue as numericNotesUnit conversion formula
joule / kilogram / KelvinShow sourceJkg×K\frac{J}{kg\times K}J / (kg × K)Show source...\text{...}-The basic specific heat unit in the SI system. The substance has specific heat of one joule per kilograme per kelwin (1 J/kg/K) if heating one kilograme sample (1 kg) by one kelvin (1 K) requires delivery of one joule of energy (1 J).Show source......
joule / gram / KelvinShow sourceJg×K\frac{J}{g\times K}J / (g × K)Show source...\text{...}-The basic specific heat unit in the SI system. The substance has specific heat of one joule per grame per kelwin (1 J/g/K) if heating one grame sample (1 g) by one kelvin (1 K) requires delivery of one joule of energy (1 J).1 Jg×K=1 J0.001 kg×K=1000 Jkg×K1\ \frac{J}{g \times K} = \frac{1\ J}{0.001\ kg \times K} = \frac{1000\ J}{kg \times K}Show source......
calorie (thermochemical) / kilogram / KelvinShow sourcecalthkg×K\frac{cal_{th}}{kg\times K}calth / (kg × K)Show source...\text{...}-The basic specific heat unit in the SI system. The substance has specific heat of one joule per kilograme per kelwin (1 calTH/kg/K) if heating one kilograme sample (1 kg) by one kelvin (1 K) requires delivery of one joule of energy (1 calTH).1 calTHkg×K=4.184 Jkg×K1\ \frac{cal_{TH}}{kg \times K} = \frac{4.184\ J}{kg \times K}Show source......
calorie (thermochemical) / gram / KelvinShow sourcecalthg×K\frac{cal_{th}}{g\times K}calth / (g × K)Show source...\text{...}-The basic specific heat unit in the SI system. The substance has specific heat of one joule per grame per kelwin (1 calTH/g/K) if heating one grame sample (1 g) by one kelvin (1 K) requires delivery of one joule of energy (1 calTH).1 calTHg×K=1 calTH0.001 kg×K=1000 calTHkg×K1\ \frac{cal_{TH}}{g \times K} = \frac{1\ cal_{TH}}{0.001\ kg \times K} = \frac{1000\ cal_{TH}}{kg \times K}Show source......
calorie (International Table) / kilogram / KelvinShow sourcecalITkg×K\frac{cal_{IT}}{kg\times K}calIT / (kg × K)Show source...\text{...}-The basic specific heat unit in the SI system. The substance has specific heat of one joule per kilograme per kelwin (1 calIT/kg/K) if heating one kilograme sample (1 kg) by one kelvin (1 K) requires delivery of one joule of energy (1 calIT).1 calITkg×K=4.1868 Jkg×K1\ \frac{cal_{IT}}{kg \times K} = \frac{4.1868\ J}{kg \times K}Show source......
calorie (International Table) / gram / KelvinShow sourcecalITg×K\frac{cal_{IT}}{g\times K}calIT / (g × K)Show source...\text{...}-The basic specific heat unit in the SI system. The substance has specific heat of one joule per grame per kelwin (1 calIT/g/K) if heating one grame sample (1 g) by one kelvin (1 K) requires delivery of one joule of energy (1 calIT).1 calITg×K=1 calIT0.001 kg×K=1000 calITkg×K1\ \frac{cal_{IT}}{g \times K} = \frac{1\ cal_{IT}}{0.001\ kg \times K} = \frac{1000\ cal_{IT}}{kg \times K}Show source......
kilocalorie / kilogram / KelvinShow sourcekcalkg×K\frac{kcal}{kg\times K}kcal / (kg × K)Show source...\text{...}-The basic specific heat unit in the SI system. The substance has specific heat of one joule per kilograme per kelwin (1 kcal/kg/K) if heating one kilograme sample (1 kg) by one kelvin (1 K) requires delivery of one joule of energy (1 kcal).1 kcalkg×K=1000 calITkg×K1\ \frac{kcal}{kg \times K} = \frac{1000\ cal_{IT}}{kg \times K}Show source......
kilocalorie / gram / KelvinShow sourcekcalg×K\frac{kcal}{g\times K}kcal / (g × K)Show source...\text{...}-The basic specific heat unit in the SI system. The substance has specific heat of one joule per grame per kelwin (1 kcal/g/K) if heating one grame sample (1 g) by one kelvin (1 K) requires delivery of one joule of energy (1 kcal).1 kcalg×K=1000 calIT0.001 kg×K=1 calITkg×K1\ \frac{kcal}{g \times K} = \frac{\cancel{1000}\ cal_{IT}}{\cancel{0.001}\ kg \times K} = 1\ \frac{cal_{IT}}{kg \times K}Show source......

Popular (temperature in Celsius degrees)#

UnitSymbolSymbol
(plain text)
Value as symbolicValue as numericNotesUnit conversion formula
joule / kilogram / degree CelsiusShow sourceJkg×C\frac{J}{kg\times ^\circ C}J / (kg × °C)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per celsius degree (1 J/kg/F) if heating one kilograme sample (1 kg) by one Celsius degree (1 K) requires delivery of one joule of energy (1 J).1 Jkg×C=1 Jkg×K1\ \frac{J}{kg \times ^{\circ}C} = 1\ \frac{J}{kg \times K}Show source......
joule / gram / degree CelsiusShow sourceJg×C\frac{J}{g\times ^\circ C}J / (g × °C)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per grame per celsius degree (1 J/g/F) if heating one grame sample (1 g) by one Celsius degree (1 K) requires delivery of one joule of energy (1 J).1 Jg×C=1 J0.001 kg×C=1000 Jkg×C1\ \frac{J}{g \times ^{\circ}C} = \frac{1\ J}{0.001\ kg \times ^{\circ}C} = \frac{1000\ J}{kg \times ^{\circ}C}Show source......
calorie (thermochemical) / kilogram / degree CelsiusShow sourcecalthkg×C\frac{cal_{th}}{kg\times ^\circ C}calth / (kg × °C)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per celsius degree (1 calTH/kg/F) if heating one kilograme sample (1 kg) by one Celsius degree (1 K) requires delivery of one joule of energy (1 calTH).1 calTHkg×C=4.184 Jkg×C1\ \frac{cal_{TH}}{kg \times ^{\circ}C} = \frac{4.184\ J}{kg \times ^{\circ}C}Show source......
calorie (thermochemical) / gram / degree CelsiusShow sourcecalthg×C\frac{cal_{th}}{g\times ^\circ C}calth / (g × °C)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per grame per celsius degree (1 calTH/g/F) if heating one grame sample (1 g) by one Celsius degree (1 K) requires delivery of one joule of energy (1 calTH).1 calTHg×C=1 calTH0.001 kg×C=1000 calTHkg×C1\ \frac{cal_{TH}}{g \times ^{\circ}C} = \frac{1\ cal_{TH}}{0.001\ kg \times ^{\circ}C} = \frac{1000\ cal_{TH}}{kg \times ^{\circ}C}Show source......
calorie (International Table) / kilogram / degree CelsiusShow sourcecalITkg×C\frac{cal_{IT}}{kg\times ^\circ C}calIT / (kg × °C)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per celsius degree (1 calIT/kg/F) if heating one kilograme sample (1 kg) by one Celsius degree (1 K) requires delivery of one joule of energy (1 calIT).1 calITkg×C=4.1868 Jkg×C1\ \frac{cal_{IT}}{kg \times ^{\circ}C} = \frac{4.1868\ J}{kg \times ^{\circ}C}Show source......
calorie (International Table) / gram / degree CelsiusShow sourcecalITg×C\frac{cal_{IT}}{g\times ^\circ C}calIT / (g × °C)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per grame per celsius degree (1 calIT/g/F) if heating one grame sample (1 g) by one Celsius degree (1 K) requires delivery of one joule of energy (1 calIT).1 calITg×C=1 calIT0.001 kg×C=1000 calITkg×C1\ \frac{cal_{IT}}{g \times ^{\circ}C} = \frac{1\ cal_{IT}}{0.001\ kg \times ^{\circ}C} = \frac{1000\ cal_{IT}}{kg \times ^{\circ}C}Show source......
kilocalorie / kilogram / degree CelsiusShow sourcekcalkg×C\frac{kcal}{kg\times ^\circ C}kcal / (kg × °C)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per celsius degree (1 kcal/kg/F) if heating one kilograme sample (1 kg) by one Celsius degree (1 K) requires delivery of one joule of energy (1 kcal).1 kcalkg×C=1000 calITkg×C1\ \frac{kcal}{kg \times ^{\circ}C} = \frac{1000\ cal_{IT}}{kg \times ^{\circ}C}Show source......
kilocalorie / gram / degree CelsiusShow sourcekcalg×C\frac{kcal}{g\times ^\circ C}kcal / (g × °C)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per grame per celsius degree (1 kcal/g/F) if heating one grame sample (1 g) by one Celsius degree (1 K) requires delivery of one joule of energy (1 kcal).1 kcalg×C=1000 calIT0.001 kg×C=1 calITkg×C1\ \frac{kcal}{g \times ^{\circ}C} = \frac{\cancel{1000}\ cal_{IT}}{\cancel{0.001}\ kg \times ^{\circ}C} = 1\ \frac{cal_{IT}}{kg \times ^{\circ}C}Show source......

Popular (temperature in Fahrenheit degrees)#

UnitSymbolSymbol
(plain text)
Value as symbolicValue as numericNotesUnit conversion formula
joule / kilogram / degree FahrenheitShow sourceJkg×F\frac{J}{kg\times ^\circ F}J / (kg × °F)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per Fahrenheit degree (1 J/kg/F) if heating one kilograme sample (1 kg) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 J).1 Jkg×F=1.8 Jkg×K1\ \frac{J}{kg \times ^{\circ}F} = 1.8\ \frac{J}{kg \times K}Show source......
joule / gram / degree FahrenheitShow sourceJg×F\frac{J}{g\times ^\circ F}J / (g × °F)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per grame per Fahrenheit degree (1 J/g/F) if heating one grame sample (1 g) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 J).1 Jg×F=1 J0.001 kg×F=1000 Jkg×F1\ \frac{J}{g \times ^{\circ}F} = \frac{1\ J}{0.001\ kg \times ^{\circ}F} = \frac{1000\ J}{kg \times ^{\circ}F}Show source......
calorie (thermochemical) / kilogram / degree FahrenheitShow sourcecalthkg×F\frac{cal_{th}}{kg\times ^\circ F}calth / (kg × °F)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per Fahrenheit degree (1 calTH/kg/F) if heating one kilograme sample (1 kg) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 calTH).1 calTHkg×F=4.184 Fkg×F1\ \frac{cal_{TH}}{kg \times ^{\circ}F} = \frac{4.184\ F}{kg \times ^{\circ}F}Show source......
calorie (thermochemical) / gram / degree FahrenheitShow sourcecalthg×F\frac{cal_{th}}{g\times ^\circ F}calth / (g × °F)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per grame per Fahrenheit degree (1 calTH/g/F) if heating one grame sample (1 g) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 calTH).1 calTHg×F=1 calTH0.001 kg×F=1000 calTHkg×F1\ \frac{cal_{TH}}{g \times ^{\circ}F} = \frac{1\ cal_{TH}}{0.001\ kg \times ^{\circ}F} = \frac{1000\ cal_{TH}}{kg \times ^{\circ}F}Show source......
calorie (International Table) / kilogram / degree FahrenheitShow sourcecalITkg×F\frac{cal_{IT}}{kg\times ^\circ F}calIT / (kg × °F)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per Fahrenheit degree (1 calIT/kg/F) if heating one kilograme sample (1 kg) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 calIT).1 calITkg×F=4.1868 Jkg×F1\ \frac{cal_{IT}}{kg \times ^{\circ}F} = \frac{4.1868\ J}{kg \times ^{\circ}F}Show source......
calorie (International Table) / gram / degree FahrenheitShow sourcecalITg×F\frac{cal_{IT}}{g\times ^\circ F}calIT / (g × °F)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per grame per Fahrenheit degree (1 calIT/g/F) if heating one grame sample (1 g) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 calIT).1 calITg×F=1 calIT0.001 kg×F=1000 calITkg×F1\ \frac{cal_{IT}}{g \times ^{\circ}F} = \frac{1\ cal_{IT}}{0.001\ kg \times ^{\circ}F} = \frac{1000\ cal_{IT}}{kg \times ^{\circ}F}Show source......
kilocalorie / kilogram / degree FahrenheitShow sourcekcalkg×F\frac{kcal}{kg\times ^\circ F}kcal / (kg × °F)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per kilograme per Fahrenheit degree (1 kcal/kg/F) if heating one kilograme sample (1 kg) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 kcal).1 kcalkg×F=1000 calITkg×F1\ \frac{kcal}{kg \times ^{\circ}F} = \frac{1000\ cal_{IT}}{kg \times ^{\circ}F}Show source......
kilocalorie / gram / degree FahrenheitShow sourcekcalg×F\frac{kcal}{g\times ^\circ F}kcal / (g × °F)Show source...\text{...}-The non-SI specific heat unit. The substance has specific heat of one joule per grame per Fahrenheit degree (1 kcal/g/F) if heating one grame sample (1 g) by one Fahrenheit degree (1 K) requires delivery of one joule of energy (1 kcal).1 kcalg×F=1000 calIT0.001 kg×F=1 calITkg×F1\ \frac{kcal}{g \times ^{\circ}F} = \frac{\cancel{1000}\ cal_{IT}}{\cancel{0.001}\ kg \times ^{\circ}F} = 1\ \frac{cal_{IT}}{kg \times ^{\circ}F}Show source......

Some facts#

  • ⓘ Remember: Specific heat is a physical quantity determining the amount of energy (heat) that should be supplied (transferred) to one unit of substance mass to raise the temperature by one unit.
  • The basic specific heat unit in the SI system is joule per kilogram per kelvin:
    Jkg×K\dfrac{J}{kg × K}
  • Specific heat is a property of substance (the so-called material constant). Also, it depends on external conditions: pressure and temperature.
  • The specific heat tells us how difficult it is to heat the given body. Substances with low specific heat change their temperature easily, whereas high ones require much more energy delivered to achieve identical effect.
  • To calculate the specific heat of the selected substance, we can use the following formula:
    c=ΔQm×ΔTc = \dfrac{\Delta Q}{m \times \Delta T}
    where:
    • cc - specific heat of the substance,
    • ΔQ\Delta Q - amount of heat delivered,
    • mm - mass of the heated sample,
    • ΔT\Delta T - noted temperature change.
  • Due to the high compressibility of gases, two values of specific heat are given in their case:
    • CpC_p - specific heat under constant pressure,
    • CvC_v - specific heat under constant volume.
    *) Compressibility is the property of a substance meaning that substance changes volume significantly under pressure.

How to convert#

  • Enter the number to field "value" - enter the NUMBER only, no other words, symbols or unit names. You can use dot (.) or comma (,) to enter fractions.
    Examples:
    • 1000000
    • 123,23
    • 999.99999
  • Find and select your starting unit in field "unit". Some unit calculators have huge number of different units to select from - it's just how complicated our world is...
  • And... you got the result in the table below. You'll find several results for many different units - we show you all results we know at once. Just find the one you're looking for.

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