Pressure units converter
Pressure units converter. Easy conversion of pascals, atmosfpheres, bars and other pressure related units.

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Inputs data - value and unit, which we're going to convert#

Value
Unit
Decimals

#

SI#

UnitSymbolSymbol
(plain text)
ValueNotes
yottapascalShow sourceYPaYPaYPa1×10-24Derived pressure unit in SI system. One yottapascal is equal to septylion of pascals: 1 YPa=1024 Pa1\ YPa= 10^{24}\ Pa
zettapascalShow sourceZPaZPaZPa1×10-21Derived pressure unit in SI system. One zettapascal is equal to sextillion of pascals: 1 ZPa=1021 Pa1\ ZPa= 10^{21}\ Pa
exapascalShow sourceEPaEPaEPa1×10-18Derived pressure unit in SI system. One exapascal is equal to quintillion of pascals: 1 EPa=1018 Pa1\ EPa= 10^{18}\ Pa
petapascalShow sourcePPaPPaPPa1×10-15Derived pressure unit in SI system. One petapascal is equal to quadrillion of pascals: 1 PPa=1015 Pa1\ PPa= 10^{15}\ Pa
terapascalShow sourceTPaTPaTPa1×10-12Derived pressure unit in SI system. One terapascal is equal to trillion of pascals: 1 TPa=1012 Pa1\ TPa= 10^{12}\ Pa
gigapascalShow sourceGPaGPaGPa1×10-9Derived pressure unit in SI system. One gigapascal is equal to billion of pascals: 1 GPa=109 Pa1\ GPa= 10^{9}\ Pa
megapascalShow sourceMPaMPaMPa0.000001Derived pressure unit in SI system. One megapascal is equal to million of pascals: 1 MPa=1000000 Pa=106 Pa1\ MPa=1000000\ Pa= 10^{6}\ Pa
kilopascalShow sourcekPakPakPa0.001Derived pressure unit in SI system. One kilopascal is equal to thausand of pascals: 1 kPa=1000 Pa=103 Pa1\ kPa=1000\ Pa= 10^{3}\ Pa
hektopascalShow sourcehPahPahPa0.01Derived pressure unit in SI system. One hektopascal is equal to hundred of pascals: 1 hPa=100 Pa=102 Pa1\ hPa=100\ Pa= 10^{2}\ Pa
pascalShow sourcePaPaPa1The basic pressure unit in the SI system. One pascal is the pressure created by acting force of one newton (1 N) to perpendicular one square meter surface (1 m2).1 Pa=1 Nm21\ Pa = 1\ \frac{N}{m^2}
decipascalShow sourcedPadPadPa10Derived pressure unit in SI system. One decipascal is equal to one tenth of pascal: 1 dPa=0.1 Pa=101 Pa1\ dPa=0.1\ Pa= 10^{-1}\ Pa
centipascalShow sourcecPacPacPa100Derived pressure unit in SI system. One centipascal is equal to one hundredth of pascal: 1 cPa=0.01 Pa=102 Pa1\ cPa=0.01\ Pa= 10^{-2}\ Pa
milipascalShow sourcemPamPamPa1000Derived pressure unit in SI system. One milipascal is equal to one thousandth of pascal: 1 mPa=0.001 Pa=103 Pa1\ mPa=0.001\ Pa= 10^{-3}\ Pa
micropascalShow sourceμPa\mu PaµPa1000000Derived pressure unit in SI system. One micropascal is equal to one millionth of pascal: 1 μPa=0.000001 Pa=106 Pa1\ \mu Pa=0.000001\ Pa= 10^{-6}\ Pa
nanopascalShow sourcenPanPanPa1000000000Derived pressure unit in SI system. One nanopascal is equal to one billionth of pascal: 1 nPa=109 Pa1\ nPa= 10^{-9}\ Pa
pikopascalShow sourcepPapPapPa1×1012Derived pressure unit in SI system. One pikopascal is equal to one trillionth of pascal: 1 pPa=1012 Pa1\ pPa= 10^{-12}\ Pa
femtopascalShow sourcefPafPafPa1×1015Derived pressure unit in SI system. One femtopascal is equal to one quadrillionth of pascal: 1 fPa=1015 Pa1\ fPa= 10^{-15}\ Pa
attopascalShow sourceaPaaPaaPa1×1018Derived pressure unit in SI system. One attopascal is equal to one quintillionth of pascal: 1 aPa=1018 Pa1\ aPa= 10^{-18}\ Pa
zeptopascalShow sourcezPazPazPa1×1021Derived pressure unit in SI system. One zeptopascal is equal to one sextillionth of pascal: 1 zPa=1021 Pa1\ zPa= 10^{-21}\ Pa
yoctopascalShow sourceyPayPayPa1×1024Derived pressure unit in SI system. One yoctopascal is equal to one septillionth of pascal: 1 yPa=1024 Pa1\ yPa= 10^{-24}\ Pa

height of the liquid column#

UnitSymbolSymbol
(plain text)
ValueNotes
centimeter mercury (0°C)Show sourcecmHgcm HgcmHg0.000750064The non-SI pressure unit. One centimetre of mercury (1 cmHg) is equivalent to the pressure acting to the floor (due to Earth gravity) by column filled up with mercury with one centimetre high (1 cm).1 cmHg=1 cm×dHg,0C×gearth102m×13.5951 kgm3×9.80665ms2==1333.22 kg×ms2×m2==1333.22 Nm2=1333.22 Pa\begin{aligned}1\ cmHg &= 1\ cm \times d_{Hg,0^{\circ}C} \times g_{earth} \approx \\&\approx 10^{-2} m \times 13.5951\ \frac{kg}{m^3} \times 9.80665 \frac{m}{s^2} =\\&= 1333.22\ \frac{kg \times m}{s^2 \times m^2} =\\&= 1333.22\ \frac{N}{m^2} = 1333.22\ Pa\end{aligned}
milimeter mercury (0°C)Show sourcemmHgmm HgmmHg0.007500638The non-SI pressure unit. One milimetre of mercury (1 mmHg) is equivalent to the pressure acting to the floor (due to Earth gravity) by column filled up with mercury with one milimetre high (1 mm).1 mmHg=1 mm×dHg,0C×gearth103m×13.5951 kgm3×9.80665ms2==133.322 kg×ms2×m2==133.322 Nm2=133.322 Pa\begin{aligned}1\ mmHg &= 1\ mm \times d_{Hg,0^{\circ}C} \times g_{earth} \approx \\&\approx 10^{-3} m \times 13.5951\ \frac{kg}{m^3} \times 9.80665 \frac{m}{s^2} =\\&= 133.322\ \frac{kg \times m}{s^2 \times m^2} =\\&= 133.322\ \frac{N}{m^2} = 133.322\ Pa\end{aligned}
inch mercury (32°F)Show sourceinHgin HginHg0.000295301The non-SI pressure unit. One inch of mercury (1 inHg) is equivalent to the pressure acting to the floor (due to Earth gravity) by column filled up with mercury with one inch high (1 in).1 inHg=1 in×dHg,32F×gearth0.0254 m×13.5951 kgm3×9.80665ms2==3386.38 kg×ms2×m2==3386.38 Nm2=3386.38 Pa\begin{aligned}1\ inHg &= 1\ in \times d_{Hg,32^{\circ}F} \times g_{earth} \approx \\&\approx 0.0254\ m \times 13.5951\ \frac{kg}{m^3} \times 9.80665 \frac{m}{s^2} =\\&= 3386.38\ \frac{kg \times m}{s^2 \times m^2} =\\&= 3386.38\ \frac{N}{m^2} = 3386.38\ Pa\end{aligned}
inch mercury (60°F)Show sourceinHgin HginHg0.000296134Inch of mercury calculated using mercury density under temperature of sixty Fahrenheit degrees (60 oF). See the inch of mercury unit for more.1 inHg=1 in×dHg,60F×gearth0.0254 m×13.5568 kgm3×9.80665ms2==3376.85 kg×ms2×m2==3376.85 Nm2=3376.85 Pa\begin{aligned}1\ inHg &= 1\ in \times d_{Hg,60^{\circ}F} \times g_{earth} \approx \\&\approx 0.0254\ m \times 13.5568\ \frac{kg}{m^3} \times 9.80665 \frac{m}{s^2} =\\&= 3376.85\ \frac{kg \times m}{s^2 \times m^2} =\\&= 3376.85\ \frac{N}{m^2} = 3376.85\ Pa\end{aligned}
centimeter water (4°C)Show sourcecmAqcm AqcmAq0.010197443The non-SI pressure unit. One centimetre of water (1 cmAq) is equivalent to the pressure acting to the floor (due to Earth gravity) by column filled up with water with one centimetre high (1 cm).1 cmAq=1 cm×dAq,4C×gearth102m×999.9720 kgm3×9.80665ms2==98.0638 kg×ms2×m2==98.0638 Nm2=98.0638 Pa\begin{aligned}1\ cmAq &= 1\ cm \times d_{Aq,4^{\circ}C} \times g_{earth} \approx \\&\approx 10^{-2} m \times 999.9720\ \frac{kg}{m^3} \times 9.80665 \frac{m}{s^2} =\\&= 98.0638\ \frac{kg \times m}{s^2 \times m^2} =\\&= 98.0638\ \frac{N}{m^2} = 98.0638\ Pa\end{aligned}
milimeter water (4°C)Show sourcemmAqmm AqmmAq0.101974429The non-SI pressure unit. One milimetre of water (1 mmAq) is equivalent to the pressure acting to the floor (due to Earth gravity) by column filled up with water with one milimetre high (1 mm).1 mmAq=1 mm×dAq,4C×gearth103m×999.9720 kgm3×9.80665ms2==9.80638 kg×ms2×m2==9.80638 Nm2=9.80638 Pa\begin{aligned}1\ mmAq &= 1\ mm \times d_{Aq,4^{\circ}C} \times g_{earth} \approx \\&\approx 10^{-3} m \times 999.9720\ \frac{kg}{m^3} \times 9.80665 \frac{m}{s^2} =\\&= 9.80638\ \frac{kg \times m}{s^2 \times m^2} =\\&= 9.80638\ \frac{N}{m^2} = 9.80638\ Pa\end{aligned}
inch water (4°C)Show sourceinAqin AqinAq0.004014742The non-SI pressure unit. One inch of water (1 inAq) is equivalent to the pressure acting to the floor (due to Earth gravity) by column filled up with water with one inch high (1 in).1 inAq=1 in×dAq,4C×gearth0.0254 m×980.638 kgm3×9.80665ms2==249.082052 kg×ms2×m2==249.082052 Nm2=249.082052 Pa\begin{aligned}1\ inAq &= 1\ in \times d_{Aq,4^{\circ}C} \times g_{earth} \approx \\&\approx 0.0254\ m \times 980.638\ \frac{kg}{m^3} \times 9.80665 \frac{m}{s^2} =\\&= 249.082052\ \frac{kg \times m}{s^2 \times m^2} =\\&= 249.082052\ \frac{N}{m^2} = 249.082052\ Pa\end{aligned}
foot water (4°C)Show sourceftAqft AqftAq0.000334562The non-SI pressure unit. One foot of water (1 ftAq) is equivalent to the pressure acting to the floor (due to Earth gravity) by column filled up with water with one foot high (1 ft).1 ftAq=1 ft×dAq,4C×gearth0.3048 m×980.638 kgm3×9.80665ms2==2988.98 kg×ms2×m2==2988.98 Nm2=2988.98 Pa\begin{aligned}1\ ftAq &= 1\ ft \times d_{Aq,4^{\circ}C} \times g_{earth} \approx \\&\approx 0.3048\ m \times 980.638\ \frac{kg}{m^3} \times 9.80665 \frac{m}{s^2} =\\&= 2988.98\ \frac{kg \times m}{s^2 \times m^2} =\\&= 2988.98\ \frac{N}{m^2} = 2988.98\ Pa\end{aligned}
inch water (60°F)Show sourceinAqin AqinAq0.004018598Inch of water calculated using water density under temperature of sixty Fahrenheit degrees (60 oF). See the inch of water unit for more.1 inAq=1 in×dAq,60F×gearth0.0254 m×13.5568 kgm3×9.80665ms2==3376.85 kg×ms2×m2==3376.85 Nm2=3376.85 Pa\begin{aligned}1\ inAq &= 1\ in \times d_{Aq,60^{\circ}F} \times g_{earth} \approx \\&\approx 0.0254\ m \times 13.5568\ \frac{kg}{m^3} \times 9.80665 \frac{m}{s^2} =\\&= 3376.85\ \frac{kg \times m}{s^2 \times m^2} =\\&= 3376.85\ \frac{N}{m^2} = 3376.85\ Pa\end{aligned}
foot water (60°F)Show sourceftAqft AqftAq0.000334883Foot of water calculated using water density under temperature of sixty Fahrenheit degrees (60 oF). See the foot of water unit for more.1 inAq=1 in×dAq,60F×gearth0.3048 m×13.5568 kgm3×9.80665ms2==2986.116 kg×ms2×m2==2986.116 Nm2=2986.116 Pa\begin{aligned}1\ inAq &= 1\ in \times d_{Aq,60^{\circ}F} \times g_{earth} \approx \\&\approx 0.3048\ m \times 13.5568\ \frac{kg}{m^3} \times 9.80665 \frac{m}{s^2} =\\&= 2986.116\ \frac{kg \times m}{s^2 \times m^2} =\\&= 2986.116\ \frac{N}{m^2} = 2986.116\ Pa\end{aligned}

Force per area#

UnitSymbolSymbol
(plain text)
ValueNotes
newton per square meterShow sourceNm2\frac{N}{m^2}N/m²1Equivalent to one pascal. See the pascal unit for more information.1 Nm2=1 Pa1\ \frac{N}{m^2} = 1\ Pa
newton per square decimeterShow sourceNdm2\frac{N}{dm^2}N/dm²0.01Equivalent to pressure created by acting one newton force (1 N) to perpendicular surface of one square decimeter (1 dm2).1 Ndm2=1 N0.01 m2=100 Nm2=100 Pa1\ \frac{N}{dm^2} = \frac{1\ N}{0.01\ m^2} = \frac{100\ N}{m^2} = 100\ Pa
newton per square centimeterShow sourceNcm2\frac{N}{cm^2}N/cm²0.0001Equivalent to pressure created by acting one newton force (1 N) to perpendicular surface of one square centimeter (1 cm2).1 Ncm2=1 N0.0001 m2=10000 Nm2=10 kPa1\ \frac{N}{cm^2} = \frac{1\ N}{0.0001\ m^2} = \frac{10000\ N}{m^2} = 10\ kPa
newton per square milimeterShow sourceNmm2\frac{N}{mm^2}N/mm²0.000001Equivalent to pressure created by acting one newton force (1 N) to perpendicular surface of one square milimeter (1 mm2).1 Nmm2=1 N106 m2=106 Nm2=1 MPa1\ \frac{N}{mm^2} = \frac{1\ N}{10^{-6}\ m^2} = \frac{10^6\ N}{m^2} = 1\ MPa
dyne per square centimeterShow sourcedynecm2\frac{dyne}{cm^2}dyne/cm²10Basic pressure unit in the centimetre-gram-second system (CGS). Equivalent to one tenth of pascal (0.1 Pa). See the pascal unit for more information.1 dyncm2=0.001 N0.0001 m2=0.1 Nm2=0.1 Pa1\ \frac{dyn}{cm^2} = \frac{\cancel{0.001}\ N}{\cancel{0.000}1\ m^2} = \frac{0.1\ N}{m^2} = 0.1\ Pa

Gravitational (metric)#

UnitSymbolSymbol
(plain text)
ValueNotes
technical atmosphereShow sourceatatat0.000010197Common name for kilogram-force per square centimeter (1 kgf/cm2) used in technical science and engineering applications. See the kilogram-force per square centimeter for more information.1 at=1 kgfcm21\ at = 1\ \frac{kgf}{cm^2}
kilogram-force per square meterShow sourcekgfm2\frac{kgf}{m^2}kgf/m²0.101971611Pressure unit in the gravitational system. One kilogram-force (1 kgf) per square meter (1 kgf/m2) is equivalent to the pressure acting on the ground after putting the one kilogram of mass (1 kg) on the top of one square meter area (1 m2).1 kgfm2=1 kg×gearthm2==1 kg×9.806651 m/s2m2==9.806551 Nm2==9.806651 Pa==0.0001 at\begin{aligned}1\ \frac{kgf}{m^2} &= \frac{1\ kg \times g_{earth}}{m^2} =\\&= \frac{1\ kg \times 9.806651\ m/s^2}{m^2} =\\&= 9.806551\ \frac{N}{m^2} =\\&= 9.806651\ Pa =\\&= 0.0001\ at\end{aligned}
kilogram-force per square centimeterShow sourcekgfm2\frac{kgf}{m^2}kgf/cm²0.000010197Pressure unit in the gravitational system. One kilogram-force (1 kgf) per square centimeter (1 kgf/cm2) is equivalent to the pressure acting on the ground after putting the one kilogram of mass (1 kg) on the top of one square centimeter area (1\ cm2).1 kgfcm2=kgf0.0001 m2=10000 kgfm2=1 at1\ \frac{kgf}{cm^2} = \frac{kgf}{0.0001\ m^2} = 10000\ \frac{kgf}{m^2} = 1\ at
kilogram-force per square milimeterShow sourcekgfmm2\frac{kgf}{mm^2}kgf/mm²1.019716109×10-7Pressure unit in the gravitational system. One kilogram-force (1 kgf) per square milimeter (1 kgf/mm2) is equivalent to the pressure acting on the ground after putting the one kilogram of mass (1 kg) on the top of one square milimeter area (1\ mm2).1 kgfmm2=kgf106 m2=106 kgfm2=100 at1\ \frac{kgf}{mm^2} = \frac{kgf}{10^{-6}\ m^2} = 10^6\ \frac{kgf}{m^2} = 100\ at
gram-force per square centimeterShow sourcegfcm2\frac{gf}{cm^2}gf/cm²0.101971611Equivalent to one kilogram-force per square meter (1 kgf/m2). See the kilogram-force per square meter unit for more information.1 gfcm2=kgfm2=0.0001 at1\ \frac{gf}{cm^2} = \frac{kgf}{m^2} = 0.0001\ at

Gravitational (imperial)#

UnitSymbolSymbol
(plain text)
ValueNotes
ton-force (long) per square inchShow sourcetflongin2\frac{tf_{long}}{in^2}tf(long)/in²6.474899006×10-8Pressure unit in the imperial gravitational system. One ton-force (long) (2240 lbs) per square inch (1 tf/in2) is equivalent to the pressure acting on the ground after putting the one long ton of mass (2240 lbs) on the top of one square inch area (1\ in2).1 tflongin2=2240 lbs×gziemiain21\ \frac{tf_{long}}{in^2} = \frac{2240\ lbs \times g_{ziemia}}{in^2}
ton-force (short) per square inchShow sourcetfshortin2\frac{tf_{short}}{in^2}tf(short)/in²7.251886887×10-8Pressure unit in the imperial gravitational system. One ton-force (short) (2000 lbs) per square inch (1 tf/in2) is equivalent to the pressure acting on the ground after putting the one short ton of mass (2000 lbs) on the top of one square inch area (1\ in2).1 tfshortin2=2000 lbs×gearthin21\ \frac{tf_{short}}{in^2} = \frac{2000\ lbs \times g_{earth}}{in^2}
kip-force per square inchShow sourcekipin2\frac{kip}{in^2}kip/in²1.450377377×10-7Pressure unit in the imperial gravitational system. One kip-force (1 kpf) per square inch (1 kpf/in2) is equivalent to the pressure acting on the ground after putting the one thousand pounds mass (1000 lbs) on the top of one square inch area (1\ in2).1 kpfin2=1000 lbs×gearthin2=1000 pdlin21\ \frac{kpf}{in^2} = \frac{1000\ lbs \times g_{earth}}{in^2} = 1000\ \frac{pdl}{in^2}
ksiShow sourceksiksiksi1.450377377×10-7Equivalent to one thousand psi (1000 psi) or one thousand pound-force per square inch (1000 lbf/in2). See the psi unit for more information.1 ksi=1000 psi=1000 lbfin21\ ksi = 1000\ psi = 1000\ \frac{lbf}{in^2}
ton-force (long) per square footShow sourcetflongft2\frac{tf_{long}}{ft^2}tf(long)/ft²0.000009324Pressure unit in the imperial gravitational system. One ton-force (long) (2240 lbs) per square foot (1 tf/ft2) is equivalent to the pressure acting on the ground after putting the one long ton of mass (2240 lbs) on the top of one square foot area (1\ ft2).1 tflongft2=2240 lbs×gearthft21\ \frac{tf_{long}}{ft^2} = \frac{2240\ lbs \times g_{earth}}{ft^2}
ton-force (short) per square footShow sourcetfshortft2\frac{tf_{short}}{ft^2}tf(short)/ft²0.000010443Pressure unit in the imperial gravitational system. One ton-force (short) (2000 lbs) per square foot (1 tf/ft2) is equivalent to the pressure acting on the ground after putting the one short ton of mass (2000 lbs) on the top of one square foot area (1\ ft2).1 tfshortft2=2000 lbs×gearthft21\ \frac{tf_{short}}{ft^2} = \frac{2000\ lbs \times g_{earth}}{ft^2}
pound-force per square footShow sourcelbfin2\frac{lbf}{in^2}lbf/in²0.000145038Pressure unit in the imperial gravitational system. One pound-force (1 lbf) per square inch (1 lbf/in2) is equivalent to the pressure acting on the ground after putting the one pound mass (1 lb) on the top of one square inch area (1\ in2).1 lbfin2=1 lb×gearthin21\ \frac{lbf}{in^2} = \frac{1\ lb \times g_{earth}}{in^2}
psiShow sourcepsipsipsi0.000145038Common name for pound-force per square inch (1 lbf/in2). See the pound-force per square inch unit for more information.1 psi=1 lbfin21\ psi = 1\ \frac{lbf}{in^2}
pound-force per square footShow sourcelbfft2\frac{lbf}{ft^2}lbf/ft²0.020885434Pressure unit in the imperial gravitational system. One pound-force (1 lbf) per square foot (1 tf/ft2) is equivalent to the pressure acting on the ground after putting the one pound mass (1 lb) on the top of one square foot area (1\ ft2).1 lbfft2=1 lb×gearthft21\ \frac{lbf}{ft^2} = \frac{1\ lb \times g_{earth}}{ft^2}
poundal per square footShow sourcepdlft2\frac{pdl}{ft^2}pdl/ft²0.067196898Pressure unit in the imperial gravitational system created by dividing the unit force poundal (1 pdl) per area unit square foot (1 ft2).

other#

UnitSymbolSymbol
(plain text)
ValueNotes
barShow sourcebarbarbar0.00001Equivalent to one hundred kilopascals (100 kPa). See the kilopascal unit for more information.1 bar=100 kPa=100 000 Pa1\ bar = 100\ kPa = 100\ 000\ Pa
milibarShow sourcembarmbarmbar0.001Equivalent to one kilopascal (1 kPa) or one thousand pascals (1000 Pa). See the pascal or kilopascal units for more information.1 mbar=1 kPa=1000 Pa1\ mbar = 1\ kPa = 1000\ Pa
microbarShow sourceμbar\mu barµbar10Equivalent to one tenth of pascal (0.1 Pa). See the pascal unit for more information.1 μbar=0.1 Pa1\ \mu bar = 0.1\ Pa
TorrShow sourceTrTrTr0.007500617Equivalent to 1/760 of standard atmosphere (1/760 atm). See the standard atmosphere unit for more information.1 Tr=1760 atm1\ Tr = \frac{1}{760}\ atm
standard atmosphereShow sourceatmatmatm0.000009869Equivalent to 760 mercury milimetres (760 mmHg) at temperature of zero celsius degrees (0 °C). Sometimes called also physical atmosphere. See the mercury milimetre unit for more information.1 atm=760 mmHg 0C=1013.25 hPa1\ atm = 760\ mmHg_{\ 0^{\circ}C} = 1013.25\ hPa

Some facts#

  • Pressure determines the force that works perpendicular to the surface. Mathematically, we can write it down in the following way:
    p=FpSp = \dfrac{F_p}{S}
    where:
    • pp - pressure,
    • FpF_p - component of force acting perpendicular to the surface,
    • SS - the area on which force is acting.
  • Pressure is scalar.
  • The pressure is usually marked with the letter p or P.
  • The pressure prevailing in the gas-filled vessel is the average force acting on the walls of this vessel. In this sense, the pressure is thus the statistical property.
  • The basic pressure unit in the SI system is pascal, which is equal to the pressure corresponding to the force of one newton acting on the surface of one square meter:
    1Pa=1N1m21 Pa = \dfrac{1 N}{1 m^2}
  • The relationship between pressure, temperature, and volume of perfect gas (i.e. one where the particles do not interact with each other) is described by the Clapeyron's equation:
    pV=nRTpV = nRT
    where:

How to convert#

  • Enter the number to field "value" - enter the NUMBER only, no other words, symbols or unit names. You can use dot (.) or comma (,) to enter fractions.
    Examples:
    • 1000000
    • 123,23
    • 999.99999
  • Find and select your starting unit in field "unit". Some unit calculators have huge number of different units to select from - it's just how complicated our world is...
  • And... you got the result in the table below. You'll find several results for many different units - we show you all results we know at once. Just find the one you're looking for.

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