Concentration of saturated solution calculator
Calculations finds out concentration (percentage or molar) of saturated solution based on substance solubility or vice versa.

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Symbolic algebra

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Calculations data - enter values, that you know here#

Percentage concentration (Cp)
=>
Solubility (ms)
(mass of substance in saturated soultion)
<=
Molar concentration (Cm)
=>
Molar mass (M)
=>
Volume (V)
=>

Units normalization#

Solubility (ms)Show source10 [g]10\ \left[g\right]
Percentage concentration (Cp)
Molar mass (M)
Volume (V)
Molar concentration (Cm)

Result: Percentage concentration (Cp)#

Summary
Used formulaShow sourceCp=msms+100100Cp=\frac{\mathrm{ms}}{\mathrm{ms}+100} \cdot 100
ResultShow source10011\frac{100}{11}
Numerical resultShow source9.090909090909090909090909090909090909090909090909090909090909091 [/00]9.090909090909090909090909090909090909090909090909090909090909091\ \left[\mathrlap{\it{/}}{^0}_{\,0}\right]
Result step by step
1Show source1010+100100\frac{10}{10+100} \cdot 100Multipled fractionsTo multiply two fractions we need to multiply numberators and denominators from first and second fractions: abcd=acbd\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}
2Show source1010010+100\frac{10 \cdot 100}{10+100}Simplify arithmetic-
3Show source100010+100\frac{1000}{10+100}Simplify arithmetic-
4Show source1000110\frac{\cancel{1000}}{\cancel{110}}Cancel terms or fractions
  • Dividing a number by itself gives one, colloquially we say that such numbers "cancel-out": aa=1 \frac{\cancel{a}}{\cancel{a}} = 1
  • to find-out the simplest form of fraction we can divide the numerator and denominator by the greatest common divisor (GCD) of both numbers.
5Show source10011\frac{100}{11}ResultYour expression reduced to the simplest form known to us.
Numerical result step by step
1Show source10011\frac{100}{11}Divided fraction-
2Show source9.0909090909090909090909090909090909090909090909090909090909090919.090909090909090909090909090909090909090909090909090909090909091ResultYour expression reduced to the simplest form known to us.
Units normalization
Show source9.090909090909090909090909090909090909090909090909090909090909091 [/00]9.090909090909090909090909090909090909090909090909090909090909091\ \left[\mathrlap{\it{/}}{^0}_{\,0}\right]

Some facts#

  • Saturated solution contains maximum dissolvable amount of substance.
  • Attempting to introduce more substance into the solution will end with the remaining undissolved substance (sludge).
  • The maximum amount of substance that can be dissolved is solubility. The solubility is often given in grams per 100 grams of solvent.
  • Solubility is substance specific. In addition, it depends on the kind of solvent and external conditions (temperature, pressure).
  • If we have the solubility of the substance (in grams per 100 grams of solvent), we can calculate the percentage concentration of saturated solution:
    Cp=msms+100×100C_p = \dfrac{m_s}{m_s + 100} \times 100
    where:
  • To calculate the molar concentration of saturated solution we additionally need to know the volume of the solution and the molar mass of the substance:
    Cm=msM×VC_m = \dfrac{m_s}{M \times V}
    where:
    • CmC_m - molar concentration of saturated solution (g/dm3g/dm^3),
    • msm_s - solubility of substance (grams per 100 grams of solvent),
    • MM - molar mass of substance (g/molg/mol),
    • VV - volume of saturated solution (dm3dm^3).


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